Snippet Name: Fixing_Column_Name_Syntax

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Created Date: 2025-06-16 13:12:41
Last Modified Date: 2025-05-31 10:32:05

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Title: Fixing Column Name Syntax
Author: user
in snowflake, i am trying to examine the column login_name. my code below reports that my syntax or column name is incorrect. what is my issue?  SHOW USERS ;
SELECT t1.*
FROM TABLE(RESULT_SCAN(LAST_QUERY_ID())) t1  
WHERE t1.login_name LIKE '%autonation%';

Author: ChatGPT
In Snowflake, the issue might be that the column name `login_name` doesn't exist in the result set of the `SHOW USERS` command. The `SHOW USERS` command in Snowflake returns a metadata result set with a predefined set of columns, and `login_name` may not be one of them.

To check the correct column names, you can first run the `SHOW USERS` command and inspect the output. Here's how you can proceed:

1. **Inspect the result of `SHOW USERS`**: 
   ```sql
   SHOW USERS;
   ```

   This will return the list of columns available, and you can confirm the exact name of the column that corresponds to login information. Snowflake typically uses a column like `NAME` or `USER_NAME` for the user login name, not `login_name`.

2. **Use the correct column name**:
   After confirming the correct column name, you can adjust your query to match it. For example, if the column is named `NAME`, your query would look like this:

   ```sql
   SELECT t1.*
   FROM TABLE(RESULT_SCAN(LAST_QUERY_ID())) t1  
   WHERE t1.NAME LIKE '%autonation%';
   ```

To summarize, verify the exact column name by inspecting the `SHOW USERS` command result and then use the correct column name in your `SELECT` statement.

Author: user
the column name is correct, and event eh case, which is all lower case, is correct

Author: ChatGPT
Thank you for the clarification! Given that the column name and case are correct, the issue might stem from how the `SHOW USERS` command and `RESULT_SCAN()` function interact in Snowflake. Specifically:

1. **`SHOW USERS` doesn't return query results directly**: The `SHOW USERS` command is a DDL command that lists users and returns results in a different format compared to a standard `SELECT` query. You cannot directly use `RESULT_SCAN()` to work with the output of a `SHOW` command in the same way you can for other queries.

2. **Use `DESCRIBE` or `SELECT` for querying the data**: Instead of using `SHOW USERS` directly with `RESULT_SCAN()`, you should use a `SELECT` statement from the `INFORMATION_SCHEMA` views or a different approach to capture user information.

Here's an updated approach using the `INFORMATION_SCHEMA.USERS` view, which is easier to work with:

### Correct Query Using `INFORMATION_SCHEMA.USERS`:
```sql
SELECT *
FROM INFORMATION_SCHEMA.USERS
WHERE login_name LIKE '%autonation%';
```

This query should return the user details and allow you to filter by the `login_name` column.

### If You Need to Use `RESULT_SCAN()`
If you want to stick with using `RESULT_SCAN()`, you need to ensure that you're capturing the result of a `SELECT` query, not a `SHOW` command. For example, you could run a `SELECT` query like this:

```sql
SELECT login_name
FROM INFORMATION_SCHEMA.USERS
WHERE login_name LIKE '%autonation%';
```

Then, capture the result of this query with `RESULT_SCAN()`:

```sql
SELECT t1.*
FROM TABLE(RESULT_SCAN(LAST_QUERY_ID())) t1  
WHERE t1.login_name LIKE '%autonation%';
```

This approach ensures you're working with a result set that can be accessed by `RESULT_SCAN()`.

Let me know if you need further adjustments!